defensive-programming
DevelopmentType safety practices including exhaustive checks, explicit return types, and Result-based error handling. Use when writing TypeScript logic that handles multiple cases or error conditions.
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Defensive Programming
Do not fall back to default
Whenever possible, cover all cases. If a new case is added in the future, TypeScript should force the developer to set behavior for it.
Force explicit return types
Makes sure all cases are covered in a function.
// TS Error: Function lacks ending return statement and return type does not include 'undefined'
export const isEnabled = (status: 'a' | 'b' | 'c'): boolean => {
if (status === 'a') {
return true;
}
if (status === 'b') {
return false;
}
};
Use exhaustive switch
Makes sure all cases are covered in a switch statement.
// TS Error: Argument of type '"c"' is not assignable to parameter of type 'never'
export const isEnabled = (status: 'a' | 'b' | 'c') => {
switch (status) {
case 'a':
return true;
case 'b':
return false;
default:
return exhaustive(status);
}
};
Use type-mapping technique
Alternative to an exhaustive switch statement.
type Schema = {
a: number;
b: number;
};
// TS Error: Property 'b' is missing in type '{ a: () => string; }' but required in type '{ a: () => void; b: () => void; }'.
const result: { [K in keyof Schema]: () => void } = {
a: () => console.log('This is A'),
};
Do not use exceptions
Unless failures are unpredictable, pass errors via return and do not throw. Throwing exceptions is not type-safe. There is a Result type that shall be used.
Bad:
try {
const result = await action();
} catch (error) {
// Possible errors cannot be typed
// ...
}
Good:
const result = await action();
if (result.error) {
const { type } = result.error;
switch (type) {
case 'ErrorA':
// ... do stuff
case 'ErrorB':
// ... do different stuff
default:
return exhaustive(type);
}
}